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发表于 2008/11/18 16:43:43
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显示全部楼层
如果使用FourthShift WEB UI版,还可以通过以下代码进行控制,在LOAD屏幕时:
在没有当前屏幕权限时,给出提示并跳转到指定屏幕.
function ScreenControl (szUID)
{
var bEntry=true;
var szSCR=document.FSWebUI.elements[3].value;
switch (szSCR)
{
case "COMT":
if(szUID == "xxx1" ){
document.FSWebUI.elements[3].value="COMI";
fsSendKey(0,27);
bEntry=false;
}
break;
case "ITMB":
if(szUID == "xxx2" ){
document.FSWebUI.elements[3].value="ITMI";
fsSendKey(0,27);
bEntry=false;
}
break;
case "xxxx":
if(szUID == "xxx1" || szUID == "xxx2" || szUID == "xxx3" ){
document.FSWebUI.elements[3].value="yyyy";
fsSendKey(0,27);
bEntry=false;
}
break;
default:
bEntry=true
break;
}
if ( bEntry == false ) alert("You haven't " + szSCR + " screen purview." );
return bEntry;
} |
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